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17 Jan 2018
6. Let f(x) = x3 – 3x2 + 1. Let M be the absolute maximum of f(t) on the interval (-1,3] and let m be the absolute minimum of f(2) on the interval -1,3). Then M + m = (a) 20 (b) 14 (c) 17 (d) 18 (e) -2
6. Let f(x) = x3 – 3x2 + 1. Let M be the absolute maximum of f(t) on the interval (-1,3] and let m be the absolute minimum of f(2) on the interval -1,3). Then M + m = (a) 20 (b) 14 (c) 17 (d) 18 (e) -2
teacherrecoLv10
19 Apr 2022
Casey DurganLv2
18 Jan 2018
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