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The combustion of octane proceeds according to the following reaction.                                 2C8H18(l)+25O2(g)→16CO2(g)+18H2O(l)If 474 moles of octane combust, what volume of carbon dioxide is produced at 19.0 degrees Celsius and 0.995 atm?

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Related questions

Part A

Determine the balanced chemical equation for this reaction.

C8H18(g)+O2(g)?CO2(g)+H2O(g)

Enter the coefficients for each compound in order, separated by commas. For example, 1,2,3,4 would indicate one mole of C8H18, two moles of O2, three moles of CO2, and four moles of H2O.

2,25,16,18

Balanced chemical equation

2C8H18(g)+25O2(g)?16CO2(g)+18H2O(g)

Part B

0.240 mol of octane is allowed to react with 0.610 mol of oxygen. Which is the limiting reactant?

oxygen

Part C

How many moles of water are produced in this reaction?

Express your answer with the appropriate units.
H2O produced =

Part D

After the reaction, how much octane is left?

Express your answer with the appropriate units.



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