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CO+2H2=CH3OH, in 1l vessel at 250 degree 0.1mol CO,0.1 mol h2 and 0.02 mol CH3OH have been preserved to react. At equlibrium find out the concentration of each substance. kc is 10.5.   please explain.                        Answer: CH3-OH mole number decrese 1.79*10^-3 and H2 mole number increase 3.58*10^-3???

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