Find the cell potential of a galvanic cell based on the following reduction half-reactions at 25 °C
Cd2+ + 2 e- → Cd E0 = -0.403 V
Pb2+ + 2 e- → Pb E0 = -0.126 V
where [Cd2+] = 0.020 M and [Pb2+] = 0.200 M.
Find the cell potential of a galvanic cell based on the following reduction half-reactions at 25 °C
Cd2+ + 2 e- → Cd E0 = -0.403 V
Pb2+ + 2 e- → Pb E0 = -0.126 V
where [Cd2+] = 0.020 M and [Pb2+] = 0.200 M.
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