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The crystalline hydrate Cd(NO3)2 · 4 H2O(s) loses water when placed in a large, closed, dry vessel at room temperature:

Cd(NO3)2 · 4 H2O(s) Cd(NO3)2(s) + 4 H2O(g)

This process is spontaneous and ∆H° is positive at room temperature. (a) What is the sign of ∆S° at room temperature? (b) If the hydrated compound is placed in a large, closed vessel that already contains a large amount of water vapor, does ∆S° change for this reaction at room temperature?

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Nestor Rutherford
Nestor RutherfordLv2
26 May 2020

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