Question

(a) Calculate the molarity of a solution that contains 0.175 mol ZnCl₂ in exactly 150 mL of solution. (b) How many moles of protons are present in 35.0 mL of a 4.50 M solution of nitric acid? (c) How many milliliters of a 6.00 M NaOH solution are needed to provide 0.350 mol of NaOH?

b) From the molarity and volume of HNO₃ we will calculate the moles of nitric acid. As HNO₃ is monoprotic acid, calculated moles will correspond to the moles of protons.