A thief plans to steal a gold sphere with a radius of 28.9 cm from a museum. If the gold has a density of 19.3 g/cm3, what is the mass of the sphere in pounds? [The volume of a sphere is V = (4/3)πr3.] Is the thief likely to be able to walk off with the gold sphere unassisted?The thief will not be able to walk off with this sphere (unless he is Popeye).

Chemistry

answer

watching

1,062

views

peacharmadillo731Lv1

18 Mar 2020

A thief plans to steal a gold sphere with a radius of 28.9 cm from a museum. If the gold has a density of 19.3 g/cm³, what is the mass of the sphere in pounds? [The volume of a sphere is V = (4/3)πr³.] Is the thief likely to be able to walk off with the gold sphere unassisted?
The thief will not be able to walk off with this sphere (unless he is Popeye).

answer

watching

1,062

views

For unlimited access to Homework Help, a Homework+ subscription is required.

You have 0 free answers left.
Get unlimited access to 3.8 million step-by-step answers.

Get unlimited access

Already have an account? Log in

Irving HeathcoteLv2

26 May 2020

Unlock all answers

Get 1 free homework help answer.

Already have an account? Log in

Join us on Discord

Chemistry Study Group

Join now

Related questions

(a) a sphere of gold with a radius of 14.1 cm. (The volume of a sphere with a radius r is V = (4/3)

r³; the density of gold is 19.3 g/cm³.)

A cube of gold that is 1.00 cm on a side has a mass of 19.3 g. A single gold atom has a mass of 197.0 amu. (a) How many gold atoms are in the cube? (b) From the information given, estimate the diameter in Å of a single gold atom. (c) What assumptions did you make in arriving at your answer for part (b)?

The number of gold atoms in 1.00 cm cube is:

b) The volume of all gold atoms is 1 cm³. We can calculate the volume of single gold atom by dividing volume of cube with the number of atoms:

If we take that gold atom is a sphere, we can calculate radius of atom:

The diameter of single gold atom is equal to 2r =3.17 Å.

c) We assumed that gold atom is a perfect sphere, and that gold spheres perfectly fill the volume of a cube, not leaving any empty space. We know that this is impossible in reality.

ivorymarten930

(a) After the label fell off a bottle containing a clear liquid believed to be benzene, a chemist measured the density of the liquid to verify its identity. A 25.0-mL portion of the liquid had a mass of 21.95 g. A chemistry handbook lists the density of benzene at 15 °C as 0.8787 g/mL. Is the calculated density in agreement with the tabulated value? (b) An experiment requires 15.0 g of cyclohexane, whose density at 25 °C is 0.7781 g/mL. What volume of cyclohexane should be used? (c) A spherical ball of lead has a diameter of 5.0 cm. What is the mass of the sphere if lead has a density of 11.34 g/cm³? (The volume of a sphere is (4/3) πr³, where r is the radius.)

Calculated density corresponds to the benzene, so an unknown liquid is benzene.

b) Volume necessary for the experiment can be calculated as:

c) First we should calculate the volume of a sphere, knowing that radius equals half of the diameter:

Then we calculate the mass as: