The relative humidity of air equals the ratio of the partial pressure of water in the air to the equilibrium vapor pressure of water at the same temperature times 100%. If the relative humidity of the air is 58% and its temperature is 68 °F, how many molecules of water are present in a room measuring 12 ft × 10 ft × 8 ft?

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Hubert KochLv2

13 May 2020

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An open vessel containing 0.205 lb of liquid water is placed in an empty room 5 ft wide, 4 ft deep, and 7 ft high, which initially contains dry air at 90 F. All the water evaporates without changing the room temperature. Use the psychrometric chart to estimate the final relative humidity, wet- bulb temperature, humid volume, dew-point temperature, and specific enthalpy of the room air. Take the molecular weight of dry air to be 29.0, and for simplicity, assume the mass of dry air in the room stays constant at its initial value.

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The relative humidity in a room is 65%. Assuming ideal gas behavior, what mass of water vapor is in the air at 25ËC if the room measures 4.2 m x 4.5 m x 3.6 m? The vapor pressure of liquid water is 23.8 torr at 25ËC.

relative humidity = actual pvap (H2O) equilibrium pvap (H2O) x100

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