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18 Dec 2019

What is the kinetic energy of the emitted electrons when cesiumis exposed to UV rays of frequency 1.9Ã1015Hz?

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Jean KeelingLv2

31 Dec 2019

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Related questions

What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of frequency 1.3Ã1015Hz?

By using the following formula, you can calculate the kinetic energy of the emitted electron:

KE=EâE0=hÎ½âhÎ½0

where h=6.63Ã10â34 Jâ s is Planck's constant, Î½=1.3Ã1015Hz is the given frequency, and Î½0=9.39Ã1014 Hz is your answer from Part A.

I am getting ridiculous numbers and can't seem to get it right.

What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of frequency \rm 1.5\times 10^{15}~Hz?

orangedinosaur998

what is the kinetic energy of the emitted electrons when cesium is exposed to uv rays of frequency of 1.2 x 10^15 hz? Express your answer in joules to three significant figures.

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