11. Given data: Molar enthalpy of diamond: h298K(diamond) = 1900 J/mol Molar entropy of graphite and diamond: s298(graphite) = 5.6 J/(Kmol), s298K(diamond) = 2.4 J/(Kmol), Molar volume of graphite and diamond: v298,1atm (graphite) = 6.0 cm3/mol, v298,1atm (diamond) = 3.4 cm3/mol Molar constant pressure heat capacity of graphite and diamond: cp(graphite) = 8.5 J/(Kmol), cp(diamond) = 6.0 J/(Kmol) Isothermal compressibility of graphite and diamond: ï¢ (graphite) =3x10-6/atm,ï ï¢ (diamond) = 2x10- 7/atm Constant pressure thermal expansion coefficient of graphite and diamond: ï¡(graphite) = 3x10- 5/K, ï¡ (diamond) = 10-5/K
Calculate: The difference in the chemical potential between diamond and graphite as a function of temperature at 1atm and plot it (assuming constant cp)
11. Given data: Molar enthalpy of diamond: h298K(diamond) = 1900 J/mol Molar entropy of graphite and diamond: s298(graphite) = 5.6 J/(Kmol), s298K(diamond) = 2.4 J/(Kmol), Molar volume of graphite and diamond: v298,1atm (graphite) = 6.0 cm3/mol, v298,1atm (diamond) = 3.4 cm3/mol Molar constant pressure heat capacity of graphite and diamond: cp(graphite) = 8.5 J/(Kmol), cp(diamond) = 6.0 J/(Kmol) Isothermal compressibility of graphite and diamond: ï¢ (graphite) =3x10-6/atm,ï ï¢ (diamond) = 2x10- 7/atm Constant pressure thermal expansion coefficient of graphite and diamond: ï¡(graphite) = 3x10- 5/K, ï¡ (diamond) = 10-5/K
Calculate: The difference in the chemical potential between diamond and graphite as a function of temperature at 1atm and plot it (assuming constant cp)
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