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18 Dec 2019

Based on the electron configuration and number of unpaired electrons, which are diamagnetic?

Electron configuration of Cu2+ is [Ar]3d(8)4s(2) and no. of unpaired electron is 2

Electron configuration of Mo4+ is [Kr]4d25s0 and no. of unpaired electron is 2

Electron configuration of Ce is [Xe] 4f1 5d1 6s2 and no. of unpaired electron is 2

Electron configuration of Sn is [Kr] 4d10 5s2 5p2 and no. of unpaired electron is 2

Electron configuration of V5+ is 1s2 2s2 2p6 3s2 3p6 and no. of unpaired electron is 0

Electron configuration of Sc2+ is 1s22s22p63s23p64s1 and no. of unpaired electron is 1

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31 Dec 2019

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Related questions

1) What are the possible orbitals for n=3?

  1. s, p, d
  2. s, p, d, f
  3. s
  4. s, p

 

2) What value of ℓ is represented by a d orbital?  

  1. 1
  2. 2  
  3. 0
  4. 3

 

3) How many orbitals are contained in the third principal level (n=3) of a given atom?

  1. 9
  2. 3
  3. 18
  4. 7
  5. 5

 

4) Which of the following statements is TRUE?

  1. The principal quantum number (n) describes the shape of an orbital.
  2. The angular momentum quantum number (ℓ) describes the size and energy associated with an orbital
  3. The magnetic quantum number (mℓ) describes the orientation of the orbital.
  4. An orbital is a path that an electron follows during its movement in an atom
  5. All of the above are true

 

5) Which of the following transitions represents the emission of a photon with the largest energy?

  1. n=2 to n=1
  2. n=3 to n=1
  3. n=6 to n=4
  4. n=1 to n=4
  5. n=2 to n=4

 

6) Choose the transition (in a hydrogen atom) below that represents the absorption of the shortest wavelength photon.

  1. n=1 to n=2
  2. n=2 to n=3
  3. n=4 to n=5
  4. n=6 to n=3
  5. n=3 to n=1

 

7) Each of the following sets of quantum numbers is supposed to specify an orbital. Choose the one set of quantum numbers that does not contain an error.

  1. n=2, ℓ =2, mℓ= +1
  2. n=2, ℓ=2, mℓ= 0
  3. n=3, ℓ=2, mℓ = -3
  4. n=4, ℓ=3, mℓ= -2
  5. n=4, ℓ=2, mℓ= +4

 

8) The element that corresponds to the electron configuration 1s2 2s2 2p6 3s2 3p6 4s1 3d5 is:

  1. titanium
  2. vanadium
  3. chromium
  4. manganese
  5. iron

 

9) Give the ground-state electron configuration for I.

  1. [Kr] 5s2 4d10 5p6
  2. [Kr] 5s2 4d10 5p5
  3. [Kr] 4d10 5p6
  4. [Kr] 5s2 5p6
  5. [Kr] 5s2 5d10 5p6

 

10) Place the following elements in order of increasing atomic radius

            P                      Ba                    Cl

  1. Ba < P < Cl
  2. P < Cl < Ba
  3. Cl < P < Ba
  4. Cl < Ba < P
  5. Ba < Cl < P

 

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