What rate law and integrated rate lets you calculate the time required to let your [CV⁺] change to half of its value at t=0? Second order rate law and its integrated rate is useful to calculate [CV⁺] to half life at t =0.

We want to find the rate law that describes how reactant concentrations affect the rate of the reaction shown by: CV⁺ + OH^- --------------- CVOH

The general form of the rate law we will find is: rate = k[CV⁺]^x [OH^-]

where x, y are the reaction orders with respect to reactanst, x+y is the overall reaction order and k is the rate constant.

so far, I have found rate = 2.0 * 10^-6 and k=1.25.

Now, I need to calculate the time needed for the concentration to be halved.

Question

What rate law and integrated rate lets you calculate the time required to let your [CV⁺] change to half of its value at t=0? Second order rate law and its integrated rate is useful to calculate [CV⁺] to half life at t =0.

We want to find the rate law that describes how reactant concentrations affect the rate of the reaction shown by: CV⁺ + OH^- --------------- CVOH

The general form of the rate law we will find is: rate = k[CV⁺]^x [OH^-]

where x, y are the reaction orders with respect to reactanst, x+y is the overall reaction order and k is the rate constant.

so far, I have found rate = 2.0 * 10^-6 and k=1.25.

Now, I need to calculate the time needed for the concentration to be halved.

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