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18 Dec 2019

What is the pH of a 0.500 M acetic acid solution with Ka = 1.8× 10^-5? The equation for the dissociation of acetic acid is:

CH3CO2H(aq) + H2O(l) <--> H3O+(aq) + CH3CO2-(aq).
A) 3.48

B) 2.48

C) 3.62

D) 2.62

Explanation with correct answer please

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Patrina Schowalter
Patrina SchowalterLv2
31 Dec 2019

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Related questions

For conjugate acid-base pairs, how are Ka and Kb related?

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