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13 Dec 2019
I am trying to find the theoretical yeild of the balance equation:
CuSO4*5H20 + 4NH3-->[Cu(NH3)4]SO4 + 4H20
Moles of CuSO4*5H20 are .0063 and there were 1.570 grams
Moles of Ammonia used are .06 (I think) (total ml of ammonia added was 4 ml and molarity is 15M)
I know the limiting reagent is the copper sulfate but I dont know how to find the theoretical yield and the theoretical mass of product produced. The molar mass is 245.75 g/mol) and I need it in moles.
I am trying to find the theoretical yeild of the balance equation:
CuSO4*5H20 + 4NH3-->[Cu(NH3)4]SO4 + 4H20
Moles of CuSO4*5H20 are .0063 and there were 1.570 grams
Moles of Ammonia used are .06 (I think) (total ml of ammonia added was 4 ml and molarity is 15M)
I know the limiting reagent is the copper sulfate but I dont know how to find the theoretical yield and the theoretical mass of product produced. The molar mass is 245.75 g/mol) and I need it in moles.
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