A particulate matter dispersoid of 1000 spherical particles witha density of 2.5 gm/cm^3 contains 300 1 micro-meter particles, 30010 micro-meter particles, and 400 40 micro-meter particles. An airpollution control device is 10% efficient on the 1 micro-meterparticles, 50% efficient on the 10 micro-meter particles, and 90%efficient on the 40 micro-meter particles. Determine the overallcontrol efficiency with respect to number of particles and particlemass.

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Particles of density 2500 kg/m3 are being studied bya manufacturer of air pollution control systems (APCSs).

The particles are of various (unknown) shapes anddiameters, so the engineers devise an optical technique to measurethe

terminal settling velocity Vt, and then planto calculate the aerodynamic equivalent diameter to use in theirAPCS

performance simulations. The tests are at STPconditions.

(a) When Vt = 2.67 ? 10-4 m/s,calculate the aerodynamic equivalent diameter Dae inmicrons. Note: You may assume

Stokes flow, but verify that the Reynolds number issmall enough for this approximation to be valid. [If not, youwill

need to use one of the other curve fits for CDas a function of Re.] Also, you will need to iterate, sinceCunningham

correction factor C depends on Dae,which in turn depends on C. [You may do the calculations byhand, but I

recommend that you use Excel or some other computerprogram to avoid calculation errors and to reduce the

monotony.]

(b) Let us define Dse = sphericalequivalent diameter as the diameter of a sphere ofactual particle density (here 2500

kg/m3) that would settle at the same(measured) terminal settling speed as the real (non-spherical)particle of the same

density. Calculate Dse in microns for themeasured value of Vt given previously.

Dse as the diameter of the actual particle,calculate Dae using Eq. (3-1), and compare with the moreexact value you

obtained in Part (a). Calculate the percentage error.If you do all the calculations correctly, your percentage errorshould

lie between -1 and -2%.

Sarvey f Chemistry I Exam #1 Spring 2018 Print Name For the multiple choice questions, write the leter of the correct answer on the space provided on the left. 1. Which of the following conversion is incorrect? a) 1 meter= 1000 millimeters b)500 ceitincters 0.5 meters c) 1 kilometer 1000 meters 010 millimeters-1ã 2. The number 638.603 rounded to 3 significent figures is a) 6386 b) 638 c) 638.60 d) 639 3. Calculate the mass of a liquid with a density of 4.2 giml and a volume of 33 ml in g. a) 7.86 b)0.13 c)138.6 4. The mass of an empty graduated cylinder was 100 g. After adding 30 ml of water the mass of the d)288 graduated cylinder became 130g. When metal beads weighing 75g were a the water level rose to 55 ml. What is the density of the metal beads? a) 136 giml d to the gradated cylinder b) 3.0 g/mi )1.2 g'ml d) 0.55 g/ml 5. A branch falls in a lake and floats on the surface. This is because a) its density is greater than water Its density is equal to wator b) Its density is less than water d) lIts density is less than air 6.A student needs to find the volume of a sample of metal pellets in order to determine its density. To find an accurate volume, she should: a) Use a ruler to measure the dimensions of the sample b) Pour the sample in an empty beaker and record the level of the dry sample c) Weigh the sample on a platform triple beam balance d) Use water displacement 7. Inthe heating curve for water, the plateau at100Â°C represents d) a andc b Specific Heat c) Liquid converting to gas a) Boiling Point 8. When water molecules gain heat energy c Temperature rises d)a and c b Temperature lowers a) They move faster 9Â·"The amount of heat required to melt l gram of ice," is defined as: Heat of Fusion Condensation a) Specific heat Heat of Vaporization e) by the water? (Heat of Fusion-3341g, Specific heat-4.184 J/gâ a. 32.3 10. 100.0 grams of water was heated from 221 â to 992 â How many kilojoules were absorbed d. 33.4 b. 32,300 d. Group 18 11. The Alkali Earth Metals are located in: c. Group 17 b. Group 2 a. Group I

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