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13 Dec 2019

How many grams of Ca3(PO4)2 precipitate can form by reacting 211 mL of 1 M CaBr2 with an excess amount of Li3PO4, given the balanced equation:

2 Li3PO4 (aq) + 3 CaBr2 (aq) --> 6 LiBr2 (aq) + Ca3(PO4)2 (s)

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Bunny Greenfelder
Bunny GreenfelderLv2
17 Dec 2019

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Consider the reaction:

2 Na3PO4(aq) + 3 Cu(NO3)2(aq) → Cu3(PO4)2(s) + 6 NaNO3(aq)

What mass of Cu3(PO4)2 can be formed when 57.9 mL of a 0.820 M solution of Na3PO4 is mixed with 42.1 mL of a 0.870 M solution of Cu(NO3)2?

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