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13 Dec 2019

Consider binding of a ligand L to a metal centerMz+, where binding is characterized by K1, K2, and K3. (When looking at tabulated data for
formation (aka binding) constants, watch whether it is logKi or -pKi.) The following are written for a neutral ligand, which bpy and phen
are. L can also undergo reactions with H+ as shown, here characterized by pKA1 and pKA2

RXN1 Mz+ + L --> MLz+ -pK1
RXN2 MLz+ + L --> ML2z+ -pK2
RXN3 ML2z+ + L --> ML3z+ -pK3
RXN4 H2L+2 + H2O --> H3O+ + HL+ pKA1
RXN5 HL+ + H2O --> H3O+ + L pKA2

1. Use the cosmic general rules. Specify the generic expressions for cM, cL, and [H3O+]. Include all ligated complexes and all species of L.
Label EQs and MBs and CB (if appropriate). Ignore activity and autoprotolysis. Note, it will be easier/neater to solve this problem later if

 β1 = K1, β2 = K1K2, and β3 = K1K2K3 are used. (Do the derivation symbolically; do not enter any numbers yet.) Define [H3O+] in 

terms of pH, which will be specified later.
2. Nickel solutions are prepared at c*M = 0:0200 F. The solutions are buffered to pH = 3:50. Bipyridine (bpy) is added until [L] = 10.00μM and
[Ni2+]= 139 nM is found by ICP-MS To the second solution, phenanthroline (phen) is added until [L] = 5.00μM and [Ni2+]= 0:201 nM.
Calculate c*bpy and c*phen. (A spreadsheet is recommended.) A similar method allows determination of formation constants. Relevant data
(Can. J. Chem. 45 2093 (1967) McBryde) are:
pKA1 pKA2 -pK1 -pK2 -pK3
bpy -0.20 4.49 7.07 6.86 6.20
phen -1.6 4.90 8.00 8.00 7.90
3. Is the fraction of NiL32+ compared to c*L the same or different for bpy and phen? Is the fraction [L] /c*L needed to form the complexes larger
for bpy or phen? Explain in terms of equilibrium constants and Le Chatelier’s principle.

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