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13 Dec 2019

This is a two part question to which I've answered the firstpart but am unsure about how to proceed with the second part.


Part 1: Write a balanced combustion reaction for natural gascomposed of 90 mol% methane and 10 mol% ethane. [Fractional molesare convenient for the subsequents calculations. Your reactionshould have .90 mol methane and .10 mol ethane on the left side. Donot include nitrogen.]


The answer I've obtained for this part of the question is:

0.9CH4 + 0.2 C2H6 + 2.5 O2 --> 2.4 H2O + 1.3 CO2


Part 2: Now note that air (not pure oxygen) flows through thecombustion chamber. Rewrite your combustion reaction from Part 1 toinclude all molecules present, whether or not they participate inthe reaction. Assume air is 80 mol% Nitrogen (N2) and 20 mol%Oxygen (O2). Assume no excess air is present.

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Trinidad Tremblay
Trinidad TremblayLv2
17 Dec 2019

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