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13 Dec 2019

Calculate the enthalpy change when 11.0 g of carbon dioxide forms from the combustion of propane.

C3H8(g) + 5O2(g) → 3CO2(g) + 2H2O(l)

ΔH = -2220 kJ

Thermochemical equivalencies:

1 mol propane = 5 mol oxygen = 3 mol carbon dioxide = 4 mol water = 2220 kJ

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Patrina Schowalter
Patrina SchowalterLv2
17 Dec 2019

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Related questions

1.Given the chemical reaction: 3 C(graphite) + 4 H2(g) --> C3H8(g)

Calculate the ∆Hrxn using Hess's Law and the following information:

C3H8(g) + 5 O2(g) --> 3 CO2(g) + 4 H2O(l) ∆H = -2220 kJ/mol

C(graphite) + O2(g) --> CO2(g) ∆H = -393.5 kJ/mol

H2(g) + 1/2 O2(g) --> H2O(l) ∆H = -285.8 kJ/mol

2.Given the chemical reaction: C3H8(g) + 5 O2(g) --> 3 CO2(g) + 4 H2O(l); ∆H = -2220 kJ/mol, calculate the heat given off when 0.48 g of C3H8 reacts with oxygen according to the reaction.

3.Given the chemical reaction: C3H8(g) + 5 O2(g) --> 3 CO2(g) + 4 H2O(l); ∆H = -2220 kJ/mol, calculate the change in temperature of 150 g of water in a calorimeter when 0.48 g of C3H8 reacts with oxygen.

The reaction for the combustion of propane is

C3H8(g)+5O2(g)⟶3CO2(g)+4H2O(l) ΔH=−526.3kcal/mol

How much heat is released when 38.9 g of propane is burned?

______ kcal

Given the following information:

Species: C3H8(g), CO2(g), H20(l), O2(g)

Delta H^(degree)(subscript f) kJ/mol: -103.8, -393.5, -285.8, 0

Calculate delta H^(degree) for the combustion of one mole of propane C3H8, according to the equation:

C3H8 + 5O2 --> 3CO2 + 4H2O + heat

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