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13 Dec 2019
A volume of 80.0mL of aqueous potassium hydroxide (KOH) wastitrated against a standard solution of sulfuric acid (H2SO4). Whatwas the molarity of the KOH solution if 21.2mL of 1.50 M H2SO4 wasneeded? The equation is 2KOH(aq)+
H2SO4(aq)?K2SO4(aq)+2H2O(l)
A volume of 80.0mL of aqueous potassium hydroxide (KOH) wastitrated against a standard solution of sulfuric acid (H2SO4). Whatwas the molarity of the KOH solution if 21.2mL of 1.50 M H2SO4 wasneeded? The equation is 2KOH(aq)+
H2SO4(aq)?K2SO4(aq)+2H2O(l)
Keith LeannonLv2
17 Dec 2019
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