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The acid C6H5COOH dissociates according to the equation: C6H5COOH (aq) â C6H5COOâ (aq) + H+ (aq) K = 6.4 x 10â5 If the initial [C6H5CO2H] is 4.59 x 10â3M, what are the equilibrium concentrations of C6H5COOâ and H+ for this dislocation reaction?

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Benzoic acid (C₆H₅COOH) and aniline (C₆H₅NH₂) are both derivatives of benzene. Benzoic acid is an acid with K_a = 6.3 × 10^–5 and aniline is a base with K_a = 4.3 × 10^–10.

(a) What are the conjugate base of benzoic acid and the conjugate acid of aniline? (b) Anilinium chloride (C₆H₅NH₃Cl) is a strong electrolyte that dissociates into anilinium ions (C₆H₅NH₃⁺) and chloride ions. Which will be more acidic, a 0.10 M solution of benzoic acid or a 0.10 M solution of anilinium chloride? (c) What is the value of the equilibrium constant for the following equilibrium?

C₆H₅COOH(aq) + C₆H₅NH₂(aq) C₆H₅COO-(aq) + C₆H₅NH₃⁺(aq)

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Benzoic acid is a weak acid that has antimicrobial properties. Its sodium salt, sodium benzoate, is a preservative found in foods, medications, and personal hygiene products. Benzoic acid dissociates in water: C6H5COOHâC6H5COOâ+H+ The pKa of this reaction is 4.2. In a 0.62 M solution of benzoic acid, what percentage of the molecules are ionized? Express the percentage numerically using two significant figures.

The acid-dissociation constant for benzoic acid (C₆H₅COOH) is 6.3 × 10^–5. Calculate the equilibrium concentrations of H₃O⁺, C₆H₅COO^–, and C₆H₅COOH in the solution if the initial concentration of C₆H₅COOH is 0.050 M.

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The acid C6H5COOH dissociates according to the equation: C6H5COOH (aq) â C6H5COOâ (aq) + H+ (aq) K = 6.4 x 10â5 If the initial [C6H5CO2H] is 4.59 x 10â3M, what are the equilibrium concentrations of C6H5COOâ and H+ for this dislocation reaction?

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The acid C6H5COOH dissociates according to the equation: C6H5COOH (aq) â C6H5COOâ (aq) + H+ (aq) K = 6.4 x 10â5 If the initial [C6H5CO2H] is 4.59 x 10â3M, what are the equilibrium concentrations of C6H5COOâ and H+ for this dislocation reaction?

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Related textbook solutions

Basic Chemistry

Principles of Chemistry Molecular Approach

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The acid C6H5COOH dissociates according to the equation: C6H5COOH (aq) â C6H5COOâ (aq) + H+ (aq) K = 6.4 x 10â5 If the initial [C6H5CO2H] is 4.59 x 10â3M, what are the equilibrium concentrations of C6H5COOâ and H+ for this dislocation reaction?