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When reacting 1-butanol with ammonium chloride and ammonium bromide, why is bromobutane the major product?
 
Is it because bromide is less electronegative than chloride?

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Related questions

Please explain why!

1-butanol yields 1-bromobutane in the presence of concentrated sulfuric acid and an excess of sodium bromide. CH3CH2CH2CH2OH (l) → CH3 CH2CH2CH2Br (l) If 16.23 mL of 1-butanol produced 13.32 g of 1-bromobutane, the percentage yield of the product equals: (Assume the density of 1-butanol is 0.81 g/mL, the molar mass of 1-butanol is 74 g/mol, and the molar mass of 1-bromobutane is 137 g/mol.)

1-butanol yields 1-bromobutane in the presence of concentrated sulfuric acid and an excess of sodium bromide.

CH3CH2CH2CH2OH (l) → CH3 CH2CH2CH2Br (l)

If 13.55 mL of 1-butanol produced 13.23 g of 1-bromobutane, the percentage yield of the product equals:

(Assume the density of 1-butanol is 0.81 g/mL, the molar mass of 1-butanol is 74 g/mol, and the molar mass of 1-bromobutane is 137 g/mol. what is The percentage yield???

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