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12 Dec 2019

Consider the titration of 100.0 mL of 0.500 M CH3NH2 by 0.250 M HCl. (Kb for CH3NH2 = 4.4×10-4) Part 1 Calculate the pH after 0.0 mL of HCl added. pH = Part 2 Calculate the pH after 25.0 mL of HCl added. pH = Part 3 Calculate the pH after 80.0 mL of HCl added. pH = Part 4 Calculate the pH at the equivalence point. pH = Part 5 Calculate the pH after 300.0 mL of HCl added. pH = Part 6 At what volume of HCl added, does the pH = 10.64? mL

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Lelia Lubowitz
Lelia LubowitzLv2
13 Dec 2019

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