In a combustion reaction between propane and oxygen, determine which reagent would be the limiting reactant when 2.00 mol of propane and 8.00 mole of oxygen are used in the balanced reaction below?

C3H8(g) + 5 O2(g) --> 3 CO2 (g) + 4 H2O (g)

answer

watching

118

views

For unlimited access to Homework Help, a Homework+ subscription is required.

You have 0 free answers left.
Get unlimited access to 3.8 million step-by-step answers.

Get unlimited access

Already have an account? Log in

Bunny GreenfelderLv2

13 Dec 2019

Unlock all answers

Get 1 free homework help answer.

Already have an account? Log in

Join us on Discord

Chemistry Study Group

Join now

Related questions

24.âLimiting Reagent problems, including Stoichiometry, Actual yield, Theoretical yield and Percent yield.

âA. I react 5.0 grams of propane, C3H8, with excess oxygen to produce water and carbon dioxide. Produce the balanced combustion equation of propane and determine the theoretical yield of water. If only 6.8 grams of water are produced what is the percent yield of water?

B. A 2.00 g sample of ammonia is mixed with 4.00 g of oxygen. Which is the limiting reagent and how much excess reactant remains on completion of the reaction? What is the theoretical yield of NO. The equation below represents this reaction. ____ NH3(g) + ____ O2(g) Â® ____ NO(g) + ____ H2O(g)

âC. If 23.54 grams of nitrogen is reacted with 11.14 grams of hydrogen. Balance the following reaction. What is the theoretical yield of this reaction and which component is the limiting reagent? If only 8.26 grams of ammonia are produced what is the percent yield? ____ N2(g) + ____ H2(g) Â® ____ NH3(g)

Consider a mixture of propane, C₃H₈, and O₂ ( 10 O₂ molecules and 3 propane molecules). O₂ is the limiting reactant.