Question

Given the following data, determine the mole ratio of iron (III) to oxalate (Fe³⁺:C₂O₄^2-) in a sample of an iron oxalate complex with the general formula K_z[Fe_x(C₂O₄)_y].wH₂O.

Mw(Fe³⁺) = 55.85 g/mol

Mw(C₂O₄^2-) = 88.02 g/mol

Step 1: Assume you have 100 g complex.

Enter your answers in the boxes provided to 3 significant figures. Do not enter units.

%m(Fe³⁺) = 11.0%

= 11.0 g in 100 g

%m(C₂O₄^2-) = 52.0%

= 52.0 g in 100 g

n(Fe³⁺) = m(Fe³⁺)/Mw(Fe³⁺)

= Answer __________ mol

n(C₂O₄^2-) = m(C₂O₄^2-)/Mw(C₂O₄^2-)

= Answer __________ mol

Step 2: Divide by smallest no. of moles (in this case Fe³⁺) to determine the ratios

Round your answer to the nearest whole number.

Ratio (C₂O₄^2-) = n(C₂O₄^2-)/ n(Fe³⁺) = Answer _________ = y

Ratio (Fe³⁺) = n(Fe³⁺)/ n(Fe³⁺) = Answer __________ = x

Therefore molar ratio of Fe³⁺:C₂O₄^2- = Answer _________ : Answer __________ = x : y