At a certain temperature and a total pressure of 1.2 ATM, the partial pressures of an equilibrium mixture 2A (g) --><-- B (g)
Are P(A)=0.60atm and P(A)=0.60atm. If the constant K(p) is 1.67, and the total pressure increased to 1.5 ATM what would be the new partial pressures of A and B at equilibrium?

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Collen VonLv2

13 Dec 2019

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