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11 Dec 2019

A 4.5085 g piece of aluminum wire with a circular cross-section is 41.90 cm long and has a density of 2.6989 g/cm3.

a)Calculate the volume of the wire.

b)What is the cross-sectional area of the wire in cm2?

c)What is its diameter in mils if 1 mil = 10–3 inches?

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Lelia Lubowitz
Lelia LubowitzLv2
13 Dec 2019
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Related questions

As part of a class project you are given 0.900 g of nichrome and asked to fabricate a wire with uniform cross-section. You use up 95% of the nichrome and make a wire with a resistance of 0.673 Ω. The resistivity of nichrome is 1.00 10-6 Ω · m and its density is 8.31 103 kg/m3. (a) What length of wire do you end up with? m (b) What is the diameter of the wire? mm

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My problem is with SIGNIFICANT FIGURE

COPPER: Copper has a density of 8.96 g/cm^3. An ingot of copperwith a mass of 57 kg (126lb) is drawn into wire with a diameter of9.50 mm. What length of wire (in meters) can be produced? [Volumeof wire = (pi)(radius)^2(length)]


d = 8.96 g/cm^3
m = 57 kg x 1000g/1 kg = 57000 g
dia = 9.50 mm x 1 cm/10mm = 0.95 cm
radius = 0.48 cm

v = m/d
v= 57000 g / 8.96 g/cm^3 = 6361.6 => 6360 cm^3

[Volume of wire = (pi)(radius)^2(length)]
6360 cm^3 = (3.14)(0.48 cm)^2(length)

Length = 6360 cm^3/ 0.72 cm
Length = 8833 cm^2
Convert to meter:
8833 cm^2 x 1m^2/ 10000 cm^2 = .8833 m^2 => .88 m^2

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