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Chemistry
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11 Dec 2019

The molar heat of vaporization of water is 44.01 kJ mol-1 at 298 K and 40.79 kJ mol-1 at 373K. Give a qualitative explanation of the difference in these two values.

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Related questions

Calculate the amount of energy (in kJ) necessary to convert 257g of liquid water from 0C to water vapor at 162C. The molar heat of vaporization of water is 40.79 kJ/mol. The specific head of water is 4.184 J/gC, and for steam is 1.99 J/gC. (Assume that specific heat values do not change over the range of temperatures in the problem.)

Liquid water is vaporized at its normal boiling point (1 bar, 373K) where the heat of vaporization is 40.7 kJ/mol. Calculate won,∆E,∆H, q_p and ∆S. Next, what is ∆Senvironment?

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