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11 Dec 2019

Naturally occurring boron consists of two isotopes:

isotope #1: natural abundance of 20.00% and a mass of 10.0129 amu,
isotope #2: natural abundance of 80.00% and a mass of 11.00931 amu.

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Patrina Schowalter
Patrina SchowalterLv2
13 Dec 2019

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Related questions

Boron has two naturally ocurring isotopes, B10 & B11, which have masses 10.0129 & 11.0093 amu, respectively. Given the average atomic mass of boron (10.81 amu), determine the percent abundance of each isotope. (explanation please)

a. 50% B10 , 50 % B11

b. 20% B10 , 80% B11

c. 98% B10 , 2% B11

d. 93% B10 , 7% B11

e. 22% B10 , 78% B11

116. Boron has only two naturally occurring isotopes. The mass of boron-10 is 10.01294 amu and the mass of boron-11 is 11.00931 amu. Calculate the relative abundances of the two isotopes.

Q11. A naturally occurring sample of an element contains only two isotopes. The first isotope has a mass of 68.9255 amu and a natural abundance of 60.11%. The second isotope has a mass of 70.9247 amu. Find the atomic mass of the element. a) 70.13 amu b) 69.72 amu c) 84.06 amu d) 69.93 amu

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