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11 Dec 2019
Methane burns according to the equation CH4(g) + 2O2 (g) --> CO2 (g) + 2H2O (g) What volume of air, which is 21% oxygen by volume, is required to burn 5.0L of methane when both are the same temperature and pressure?
Methane burns according to the equation CH4(g) + 2O2 (g) --> CO2 (g) + 2H2O (g) What volume of air, which is 21% oxygen by volume, is required to burn 5.0L of methane when both are the same temperature and pressure?
Jean KeelingLv2
13 Dec 2019