answer

watching

views

11 Dec 2019

In an acid-base titration, 24.88 mL of an NaOH solution are needed to neutralize 26.43 mL of a 0.1049 M HCl solution, To find the molarity of the NaOH solution, we can use the following procedure: a First note the value of MH- in the HCl solution. b. Find MOH- in the NaOH solution. c. Obtain MNaOH from MOH-.

answer

watching

1,299

views

For unlimited access to Homework Help, a Homework+ subscription is required.

You have 0 free answers left.
Get unlimited access to 3.8 million step-by-step answers.

Get unlimited access

Already have an account? Log in

Elin HesselLv2

13 Dec 2019

Unlock all answers

Get 1 free homework help answer.

Already have an account? Log in

Join us on Discord

Chemistry Study Group

Join now

Related questions

advance study assignment molar mass of an acid.
1. 7.2ml of 6.0M NaOH there are in 7.2ml of 6.0 M NaOH are diluted with water to a volume of 400.0ml. you are asked to find the molarity of the resulting must be solution.
a. first find out how many moles of NaOH there are in 7.2ml of 6.0 M NaOH. use equation 1. note that the volume must be in liters.
b. since the total number of moles of NaOH is not changed on dilution, the molarity after dilution can also be found by equation 1. using the final volume of the solution. calulate the molarity.
2. in an acid base titration, 21.16ml of an NaOH solution are needed to neutralize 20.04ml of a 0.0997M HCL solution. to find the molarity of the NaOH solution, we can use the following procedures.
a. first note the value of MH+ in HCL solution.
b. find MOH- in NaOH solution equation 3
c. obtain M NAOH from M OH
3. a 0.3012g sample of an unknown monoprotic acid requires 24.13ml of 0.0944 M NaOH of neutralization to a phenolpthalein end point. there are 0.32ml of 0.0997 M HCL used for back titration.
a. how many moles of OH- are used?
how many moles of H+ from HCL?
_____moles OH- _______ moles H+
b. how many moles of H+ are there in the solid acid? use eq 5.
____moles H+ in solid
c. what is the molar mass of the unknown acid? use equation 4.
______g/mol

step by step and answer all
thank you

In an acid-base titration, 26.81 mL of a NaOH solution are needed to neutralize 26.98 mL of a 0.1490 M HCl solution. Find the molarity of the NaOH solution.

Please Provide detailed explaination with equations and fulldetailed solutions....

Also, pretty positive that my answers to question 1-2 A are correct, so my only concern and what I need help with is the remainder of the questions, although feel free to verify my answers...Thank you!

1) 7.0 mL of 6.0M NaOH are diluted with water to avolume of 400mL. You are asked to find the molarity of theresulting solution.
a. First find out how many moles ofNaOH there are in 7.0 mL of 6.0 M NaOH. Note: thevolume must be in liters.

No . of moles of NaOH , n = Molarity * Volume in L

= 6.0 M * 0.007 L

= 0.042 moles

b. Since the total number of molesof NaOH is not changed on dilution, the molarity afterdilution can also be found, using the final volume of thesolution. Calculate the molarity.
MV = M'V'

6.0 M * 0.007L = M * 0.4 L

M = 0.105M

2) In an acid-base titration, 22.13 mL of an NaOH solutionare needed to neutralize 24.65 mL of a 0.1094 M HCl solution. To find the molarity of the NaOH solution, we can use the followingprocedure:

MV =M'V'

M * 0.02213 L = 0.1094 * 0.02465 L

M = 0.1218 M

b. Find M_OH- in the NaOHsolution.
_______________M

c. Obtain M _NaOH from M_OH- .
_______________M

3) A 0.2678g sample of an unknown acid requires 27.21 mL of0.1164 M NaOH for neutralization to a phenolphalein endpoint. There are 0.35 mL of 0.1012 M HCl used forback-titration.

a. How many moles of OH^- are used? How many moles of H+ from HCl?

___________moles OH^- ____________molesH⁺

b. How many moles of H⁺ are there in thesolid acid?
____________moles H⁺ in solid

c. What is the molar mass of the unknownacid?
_______________ g

Weekly leaderboard

Home

Homework Help 3,900,000

Chemistry 830,000

Unlock all answers

Related textbook solutions

Basic Chemistry

Principles of Chemistry Molecular Approach

Chemistry: Structure and Properties

Principles of Chemistry Molecular Approach

Chemistry: A Molecular Approach

Chemistry: A Molecular Approach

Principles of Chemistry: A Molecular Approach

Chemistry: The Central Science

Related questions

Weekly leaderboard