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11 Dec 2019
4.60 mol of solid A was placed in a sealed 1.00-L container and allowed to decompose into gaseous B and C. The concentration of B steadily increased until it reached 1.10 M, where it remained constant.
A(s)=B(g)+C(g)
Then, the container volume was doubled and equilibrium was re-established. How many moles of A remain
? mol A
4.60 mol of solid A was placed in a sealed 1.00-L container and allowed to decompose into gaseous B and C. The concentration of B steadily increased until it reached 1.10 M, where it remained constant.
A(s)=B(g)+C(g)
Then, the container volume was doubled and equilibrium was re-established. How many moles of A remain
? mol A
Jarrod RobelLv2
13 Dec 2019
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