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11 Dec 2019

In the balanced equation 2 C8H18(g) + 25 O2 (g) -> 16 CO2(g)+18H2O(g)

Part B .370 mol of octane is allowed to react with .810mol ofoxygen. Which is the limiting reactant?

Part C How many moles of water are produced in thisreaction?

Part D After the reaction , how much octane is left?

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Reid Wolff
Reid WolffLv2
12 Dec 2019

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Related questions

Part A

Determine the balanced chemical equation for this reaction.

C8H18(g)+O2(g)?CO2(g)+H2O(g)

Enter the coefficients for each compound in order, separated by commas. For example, 1,2,3,4 would indicate one mole of C8H18, two moles of O2, three moles of CO2, and four moles of H2O.

2,25,16,18

Balanced chemical equation

2C8H18(g)+25O2(g)?16CO2(g)+18H2O(g)

Part B

0.240 mol of octane is allowed to react with 0.610 mol of oxygen. Which is the limiting reactant?

oxygen

Part C

How many moles of water are produced in this reaction?

Express your answer with the appropriate units.
H2O produced =

Part D

After the reaction, how much octane is left?

Express your answer with the appropriate units.

The octane rating of gasoline is a relationship of the burningefficiency of the given gasoline mixture to the burning efficiencyof octane (C8H18). (Figure1) Like most hydrocarbons, octane reacts with oxygen gas toproduce carbon dioxide and water. The unbalanced equation for thisreaction is C8H18(g) + O2(g) ? CO2(g) + H2O(g).

Balanced chemical equation is 2C8H18(g) + 25O2(g) ?16CO2(g) + 18H2O(g).

A)-How many moles of water are produced in this reaction?

B)- After the reaction, how much octane is left?

Please, show me

After the reaction, how much octane is left?

2 C8H18Ā + 25 O2 --> 16 CO2 + 18 H2O

0.660 mol of octane is allowed to react with 0.780 mol of oxygen. Oxygen is the limiting reactant.
After the reaction, how much octane is left?

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