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11 Dec 2019
The value of Ka for nitrous acid (HNO2) at 25 °C is 4.5×10−4.
a. Write the chemical equation for the equilibrium that corresponds to Ka
1. H+(aq)+NO−2(aq)⇌HNO2(aq)
2. HNO2(aq)⇌H+(aq)+NO−2(aq)
3. HNO2(aq)⇌H−(aq)+NO+2(aq)
4. HNO2(aq)+H+(aq)⇌H2NO+2(aq)
5. HNO2(aq)+H−(aq)⇌H2NO+2(aq)
b. By using the value of Ka, calculate ΔG° for the dissociation of nitrous acid in an aqueous solution.
c. What is the value of ΔG at equilibrium?
d. What is the value of ΔG when [H+] = 5.9×10−2 M , [NO−2] = 6.7×10−4 M , and [HNO2] = 0.21 M ?
The value of Ka for nitrous acid (HNO2) at 25 °C is 4.5×10−4.
a. Write the chemical equation for the equilibrium that corresponds to Ka
| 1. H+(aq)+NO−2(aq)⇌HNO2(aq) |
| 2. HNO2(aq)⇌H+(aq)+NO−2(aq) |
| 3. HNO2(aq)⇌H−(aq)+NO+2(aq) |
| 4. HNO2(aq)+H+(aq)⇌H2NO+2(aq) |
| 5. HNO2(aq)+H−(aq)⇌H2NO+2(aq) |
b. By using the value of Ka, calculate ΔG° for the dissociation of nitrous acid in an aqueous solution.
c. What is the value of ΔG at equilibrium?
d. What is the value of ΔG when [H+] = 5.9×10−2 M , [NO−2] = 6.7×10−4 M , and [HNO2] = 0.21 M ?
Kenneth DuqueLv10
28 Nov 2020
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