A certain weak acid, HA, with a Ka value of 5.61 x 10^-6 , istitrated with NaOH.

Part A: A solution is made by mixing 9.00 mmol (millimoles) of HAand 2.00 mmol of the strong base. What is the resulting pH?

Part B: More strong base is added until the equivalence point isreached. What is the pH of this solution at the equivalence pointif the total volume is 64.0mL ?

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A certain weak acid, HA,with a Kavalue of 5.61x10^(-6), is titrated with NaOH.

A.) A solution is made by mixing 9.00

mmol(millimoles) of HAand 1.00mmolof the strong base. What is the resulting pH?

pH = 4.35

B.)Morestrong base is added until the equivalence point is reached. Whatis the pH of this solution at the equivalence point if the totalvolume is 80.0 mL?

pH=??????

I got A can't understand how to do B plz help.

ochremallard624

A certain weak acid, HA, with a Ka value of 5.61Ã10â6, is titrated with NaOH.

Part A

A solution is made by titrating 9.00 mmol (millimoles) of HA and 1.00 mmol of the strong base. What is the resulting pH?

Part B

More strong base is added until the equivalence point is reached. What is the pH of this solution at the equivalence point if the total volume is 50.0 mL ?

certain weak acid, HA, with a Ka value of 5.61Ã10â6, is titrated with NaOH. Part A A solution is made by titrating 9.00 mmol (millimoles) of HA and 3.00 mmol of the strong base. What is the resulting pH? part 2 More strong base is added until the equivalence point is reached. What is the pH of this solution at the equivalence point if the total volume is 77.0 mL ?