How many milliliters of a 2.31 M solution of glucose,C6H12O6 , molar mass = 180.155g/mol , do you need to obtain 25.0 g of glucose?

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28 Nov 2019

How many milliliters of a 2.31 M solution of glucose,C₆H₁₂O₆ , molar mass = 180.155g/mol , do you need to obtain 25.0 g of glucose?

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30.0 g of glucose (C₆H₁₂O₆, molar mass = 180.16 g/mol) is dissolved in 100 grams of water (molar mass 18.02). What is the mole fraction of water in solution? Note: glucose is a non-volatile solute.

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An isotonic solution of glucose contains 5.31 g of glucose (C₆H₁₂O₆, Molar Mass = 180.16 g/mol) in 100.0 mL of solution. Imagine this solution is separated from pure water by a semi-permeable membrane. What would the osmotic pressure of the solution be at 293.2 K? Enter your answer in the unit of atmospheres.

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How many milliliters of a 2.31 M solution of glucose,C₆H₁₂O₆ , molar mass = 180.155g/mol , do you need to obtain 25.0 g of glucose?

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