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26 Nov 2019

What is the ratio of effusion rates for O2 and Kr

At a given Temp and Pressure, it took 2:56 minutes for 1.0L of Krto effuse. How long would
it take O2 to effuese under same conditions?

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Patrina Schowalter
Patrina SchowalterLv2
2 Aug 2019

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Related questions

A gas of unknown molecular mass was allowed to effuse through a small opening under constant-pressure conditions. It required 67 s for 1.0 L of the gas to effuse. Under identical experimental conditions it required 24 s for 1.0 L of O2 gas to effuse. Calculate the molar mass of the unknown gas. (Remember that the faster the rate of effusion, the shorter the time required for effusion of 1.0 L; that is, rate and time are inversely proportional.)

A gas of unknown molecular mass was allowed to effuse through a small opening under constant-pressure conditions. It required 105 s for 1.0 L of the gas to effuse. Under identical experimental conditions it required 30 s for 1.0 L of O2 gas to effuse.

Calculate the molar mass of the unknown gas. (Remember that the faster the rate of effusion, the shorter the time required for effusion of 1.0 L; that is, rate and time are inversely proportional.)

Express your answer using two significant figures.

An effusion container is filled with 1 L of an unknown gas. It takes 123 s for the gas to effuse into a vacuum. From the same container under the same conditions--same temperature and initial pressure, it takes 369 s for 1.00 L of O2 gas to effuse. Calculate the molar mass (in grams/mol) of the unknown gas.

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