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23 Nov 2019
The activation energy of a certain reaction is 38.KJ/mol . At 28C , the rate constant is 0.0190S^-1 . At what temperature in degrees Celsius would this reaction go twice as fast?Given that the initial rate constant is 0.0190S^-1 at an initial temperature of 28C , what would the rate constant be at a temperature of 140C for the same reaction described in Part A?
The activation energy of a certain reaction is 38.KJ/mol . At 28C , the rate constant is 0.0190S^-1 . At what temperature in degrees Celsius would this reaction go twice as fast?Given that the initial rate constant is 0.0190S^-1 at an initial temperature of 28C , what would the rate constant be at a temperature of 140C for the same reaction described in Part A?
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