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19 Nov 2019
Which compounds react to form this compound? I. 2-methylpropanal II. methanal III. 1-butanol IV. Ethanol A) I and II B) I and III C) I and IV D) II and III Which statement about these compounds is true? I. CH_3CH_2CH_2CONH_2 II CH_3COCH_2CH_2NH_2 A) I and II have comparable basicity because both have an NH_2 group. B) I is more basic than II because the carbonyl group, through its electron-withdrawing effect, increases the availability of nitrogen's nonbonded pair of electrons. C) II is more basic than I because nitrogen's nonbonded pair of electrons in II is more available for bonding to a proton than is the case in compound I. D) None of these statements is completely true. An unknown compound C_3H_6O is converted into C_3H_6O_2 on reaction with potassium dichromate (oxidation). The unknown must be: A) propanol B) propanal C) acetone D) CH_2=CHCH_2OH Arrange these compounds in order of increasing boiling point. I. CH_3CH_2CH_2COOH II. CH_3CH_2COOCH_3 III. (CH_3)_2CHCH_2CH_2OH A) I
Which compounds react to form this compound? I. 2-methylpropanal II. methanal III. 1-butanol IV. Ethanol A) I and II B) I and III C) I and IV D) II and III Which statement about these compounds is true? I. CH_3CH_2CH_2CONH_2 II CH_3COCH_2CH_2NH_2 A) I and II have comparable basicity because both have an NH_2 group. B) I is more basic than II because the carbonyl group, through its electron-withdrawing effect, increases the availability of nitrogen's nonbonded pair of electrons. C) II is more basic than I because nitrogen's nonbonded pair of electrons in II is more available for bonding to a proton than is the case in compound I. D) None of these statements is completely true. An unknown compound C_3H_6O is converted into C_3H_6O_2 on reaction with potassium dichromate (oxidation). The unknown must be: A) propanol B) propanal C) acetone D) CH_2=CHCH_2OH Arrange these compounds in order of increasing boiling point. I. CH_3CH_2CH_2COOH II. CH_3CH_2COOCH_3 III. (CH_3)_2CHCH_2CH_2OH A) I
Patrina SchowalterLv2
19 Aug 2019