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19 Nov 2019
Solving the Rydberg equation for energy change gives Delta E = R_infinity hc [1/n^2_1 - 1/n^2_2] where the Rydberg constant R_infinity for hydrogen-like atoms is 1.097 times 10^7 m^-1 Z^2, and Z is the atomic number. (a) Calculate the energies needed to remove an electron from the n = 1 state and the n = 6 state in the Li^2+ ion. n = 1 (Enter your answer in scientific notation.) (b) What is the wavelength (in nm) of the emitted photon in a transition from n = 6 to n = 1? nm
Solving the Rydberg equation for energy change gives Delta E = R_infinity hc [1/n^2_1 - 1/n^2_2] where the Rydberg constant R_infinity for hydrogen-like atoms is 1.097 times 10^7 m^-1 Z^2, and Z is the atomic number. (a) Calculate the energies needed to remove an electron from the n = 1 state and the n = 6 state in the Li^2+ ion. n = 1 (Enter your answer in scientific notation.) (b) What is the wavelength (in nm) of the emitted photon in a transition from n = 6 to n = 1? nm
Nestor RutherfordLv2
30 Apr 2019