1
answer
0
watching
656
views
18 Nov 2019
Organic Chemistry II, CHEM 207 QUIZ #3 1) In electrophilic aromatic substitution reactions the nitro group is A) a m-director since it destabilizes the meta sigma complex more than the ortho, para. B) a m-director since it destabilizes the meta sigma complex less than the ortho, para c) an o,p-director since it stabilizes the ortho, para sigma complex more than the meta. an o,p-director since it stabilizes the ortho, para sigma complex less than the imeta. E) hone of the above. 2) The nitration of anisole: A) proceeds more rapidly than the nitration of benzene and yields predominantly the meta product. B) proceeds more rapidly than the nitration of benzene and yields predominantly the ortho, para products C)proceeds more slowly than the nitration of benzene and yields predominantly the meta product proceeds more slowly than the nitration of benzene and yields predominantly the ortho, para products. E) proceeds at the same rate as the nitration of benzene and yields predominantly the meta product 3) Which of the following is the strongest activating group in electrophilic aromatic substitution reactions? A) -CH2CH3 B) -OCH3 C)-co2CH3 D) -N(CH3) 4) Rank the following groups in order of increasing activating power in electrophilic aromatic substitution reacti -OCH3, -OCOCH2CH3, -CH2CH3. -Br. 34 2. 5) In electrophilic aromatic substitution reactions a bromine substituent: A) is a deactivator and a m-director B) is a deactivator and an o,p-director. C) is an activator and a m-director. D) is an activator and an o,p-director. E) none of the above 6) Provide a series of synthetic steps by which 2-bromo-4-nitrobenzoic acid can be prepared from tolyene
Organic Chemistry II, CHEM 207 QUIZ #3 1) In electrophilic aromatic substitution reactions the nitro group is A) a m-director since it destabilizes the meta sigma complex more than the ortho, para. B) a m-director since it destabilizes the meta sigma complex less than the ortho, para c) an o,p-director since it stabilizes the ortho, para sigma complex more than the meta. an o,p-director since it stabilizes the ortho, para sigma complex less than the imeta. E) hone of the above. 2) The nitration of anisole: A) proceeds more rapidly than the nitration of benzene and yields predominantly the meta product. B) proceeds more rapidly than the nitration of benzene and yields predominantly the ortho, para products C)proceeds more slowly than the nitration of benzene and yields predominantly the meta product proceeds more slowly than the nitration of benzene and yields predominantly the ortho, para products. E) proceeds at the same rate as the nitration of benzene and yields predominantly the meta product 3) Which of the following is the strongest activating group in electrophilic aromatic substitution reactions? A) -CH2CH3 B) -OCH3 C)-co2CH3 D) -N(CH3) 4) Rank the following groups in order of increasing activating power in electrophilic aromatic substitution reacti -OCH3, -OCOCH2CH3, -CH2CH3. -Br. 34 2. 5) In electrophilic aromatic substitution reactions a bromine substituent: A) is a deactivator and a m-director B) is a deactivator and an o,p-director. C) is an activator and a m-director. D) is an activator and an o,p-director. E) none of the above 6) Provide a series of synthetic steps by which 2-bromo-4-nitrobenzoic acid can be prepared from tolyene
Hubert KochLv2
29 Aug 2019