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18 Nov 2019

accodong to the report. benzoic acid solution -weight out 0.61 (5.0 mmoles) of benzoic acid and place the acids in 250-ml flask with 150ml of water add and heated. after rinsing with water to transfer acid. when the solution cool adjust the volume to 250-ml to give 0.020M solution of benzoic acid.
Naoh solution-with one pellets of naoh dissolve in 100 ml of water and rinsed. alternately, use a stock solution of 0.02 Naoh. place a 10.0ml sample of the 0.02M benzoic acid in small flask and add one drop of phenolphthalein solution. titrate to a pink end point. repeat with a 10.0ml sample, average the buret readings and calculate the molarity of Naoh. note -the first titration was 6ml and the second was 6ml.
calculate
molarity of benzoic acid solution
mililiters of Naoh solution (average )
molarity of Naoh solution.
pls show full calculate in other to understand

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Nelly Stracke
Nelly StrackeLv2
20 Aug 2019

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