Ignore the circled answers, some of them are wrong but I don't know which. What are the correct answers for questions 13-16?
13. Which of the following is not correct concerning noncompetitive inhibition? a. The KM is the same in the presence of the inhibitor b. The V max is always less in the presence of an inhibitor c. The inhibitor binds to the enzyme at the same active site as e. The enzyme can bind the substrate and the inhibitor at the same time forming an ESI complex. of the above are correct 14. Pyridoxine is a water soluble organic substance that is not synthesized by humans. It is chemically converted to Pyridoxal Phosphate which is required by ami enzymes that catalyze chemical changes of amino acids. Which of the following statements is correct? a. Pyridoxal Phosphate is a transferase enzyme. Pyridoxine is a coenzyme. b. Pyridoxine is a vitamin Pyridoxal Phosphate is a vitamin e. None of the above is correct Optimum pH 15. Consider the pH profile of pepsin shown to the ri ght. What can be concluded about the catalytic residue in the active site of pepsin? The catalytic residue is probably a Histidine residue. The catalytic residue is probably an Aspartic acid residue and the active form Enzyme of this residue is the protonated form activity c. The catalytic residue is probably a Glutamic acid residue and the active form of this residue is the deprotonated form d. The catalytic residue is probably a protonated N-terminal amino group which acts as a nucleophile None of these. There is not enough information to make a conclusion pH 16. Which of the following is correct concerning the structure of the compound shown to CH2OH the right? a. This is a "reducing" sugar b. This disaccharide is not digested in humans and serves as roughage in our diet c. disaccharide contains a pentos d. This sugar is not water soluble because it contains a B glycoside bond. CH2OH of this sugar equimolar amounts of D-Glucose and D- O HO Fructose, sometimes referred to as "invert sugar CH2OH
