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28 Sep 2019
2Al(s)+3Cl_2(g)--->2AlCl_3(s)
You are given 19.0 g of aluminum and 24.0 g of chlorine gas.
Part A:
If you had excess chlorine, how many moles of of aluminum chloridecould be produced from 19.0 g of aluminum?
Part B:
If you had excess aluminum, how many moles of aluminum chloridecould be produced from 24.0 g of chlorine gas, Cl_2?
2Al(s)+3Cl_2(g)--->2AlCl_3(s)
You are given 19.0 g of aluminum and 24.0 g of chlorine gas.
Part A:
If you had excess chlorine, how many moles of of aluminum chloridecould be produced from 19.0 g of aluminum?
Part B:
If you had excess aluminum, how many moles of aluminum chloridecould be produced from 24.0 g of chlorine gas, Cl_2?
You are given 19.0 g of aluminum and 24.0 g of chlorine gas.
Part A:
If you had excess chlorine, how many moles of of aluminum chloridecould be produced from 19.0 g of aluminum?
Part B:
If you had excess aluminum, how many moles of aluminum chloridecould be produced from 24.0 g of chlorine gas, Cl_2?
14 Feb 2023
Patrina SchowalterLv2
28 Sep 2019
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