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The printed label on a bottle of commercial vinegar states thatthe acetic acid
concentration is 5%.
(a) If the manufacturer had reported two significant figures in theconcentration, what
would the percentage range be so that all values would round to5%?
(b) Calculate the concentration in molarity of the upper and lowervalues from (a).
The molecular weight of acetic acid is 60.05 g/mol. How many digitscan you
report in your answers?
(c) What assumption did you make to calculate the concentrations inpart (b)?
(d) What is the percentage difference in the concentrations youcalculated in part (b)?
Explain what value you chose for the denominator in thiscalculation?


PLEASE HELP!


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Beverley Smith
Beverley SmithLv2
28 Sep 2019

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