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16 Nov 2019
Ammonium cyanate (NH_4NCO) rearranges in water to give urea ((NH_2)_2CO) according to the following chemical equation: NH_4NCO(aq) rightarrow (NH_2)_2CO(aq) Given the information below, what is the rate law for the above reaction? What is the overall order of the reaction? What is the value of the rate constant for this reaction? If the original concentration of NH_4NCO in solution is 0.229 M, how long will it take for the concentration to decrease to 5.40 times 10^-2 M? Suppose the rate of rearrangement of NH_4NCO to urea is done at 0 degree C and 77 degree C and is found to be 4.31 times 10^-5 M h^-1 and 5.39 times 10^-4 M h^-1, respectively. If [NH_4NCO] = 0.1 M for both experiments then determine the activation energy for the reaction as well as the pre-exponential factor, A.
Ammonium cyanate (NH_4NCO) rearranges in water to give urea ((NH_2)_2CO) according to the following chemical equation: NH_4NCO(aq) rightarrow (NH_2)_2CO(aq) Given the information below, what is the rate law for the above reaction? What is the overall order of the reaction? What is the value of the rate constant for this reaction? If the original concentration of NH_4NCO in solution is 0.229 M, how long will it take for the concentration to decrease to 5.40 times 10^-2 M? Suppose the rate of rearrangement of NH_4NCO to urea is done at 0 degree C and 77 degree C and is found to be 4.31 times 10^-5 M h^-1 and 5.39 times 10^-4 M h^-1, respectively. If [NH_4NCO] = 0.1 M for both experiments then determine the activation energy for the reaction as well as the pre-exponential factor, A.
Casey DurganLv2
2 Aug 2019