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16 Nov 2019
What is the approximate ph at the equivalence point of a weak acid-strong base titration if 25 mL of aqueous formic acid requires 29.80 mL of 0.2567 M NaOH? Ka = 1.8 x 10^-4
How do you solve this without the M1V1 = M2V2 ?
Answer given: 8.44
What is the approximate ph at the equivalence point of a weak acid-strong base titration if 25 mL of aqueous formic acid requires 29.80 mL of 0.2567 M NaOH? Ka = 1.8 x 10^-4
How do you solve this without the M1V1 = M2V2 ?
Answer given: 8.44
Trinidad TremblayLv2
3 May 2019
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