Question

Using data from the table below, calculate the freezing and boiling points of 2.04 g KBr and 4.82 g glucose (C6H12O6) in 188 g H2O. Given: Kb of H2O: 0.51 C/m; Kf of H2O: 1.86 C/m.I'm not really looking for the answer (though I won't complain if you provide it), I'm just confused as to what I need to do if I have a solution with two solutes.I know I need to use the equation Delta(Tb)=Kb*m*i and Delta(Tf)=Kf*m*i.I know how to figure it out if it's only 1 solute but I'm confused as to what to do if I have two solutes.(By the way, I put this under my course ENGR 202; it's actually for ENGR 106 but it wasn't wanting to load that course. Anyways, that's trivial.