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A copper ore contained Cu2S and CuS plus 10% inert impurities. When 200 g of the ore was roasted, it yielded 150.8 g of 90.0% pure copper and sulfur dioxide gas. What is the percentage of Cu2S in the ore? Given Cu2S + O2-->2Cu + SO2 CuS+ O2-->Cu+ SO2

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Patrina Schowalter
Patrina SchowalterLv2
28 Sep 2019

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