1
answer
0
watching
824
views
11 Nov 2019

For a first-order reaction, the half-life is constant. It depends only on the rate constant k and not on the reactant concentration. It is expressed as t1/2=0.693k For a second-order reaction, the half-life depends on the rate constant and the concentration of the reactant and so is expressed as t1/2=1k[A]0

Part A

A certain first-order reaction (A→products) has a rate constant of 7.50×10−3 s−1 at 45 ∘C. How many minutes does it take for the concentration of the reactant, [A], to drop to 6.25% of the original concentration?

Part B

A certain second-order reaction (B→products) has a rate constant of 1.10×10−3 M−1⋠s−1 at 27 ∘C and an initial half-life of 204 s . What is the concentration of the reactant B after one half-life?

For unlimited access to Homework Help, a Homework+ subscription is required.

Beverley Smith
Beverley SmithLv2
1 Mar 2019

Unlock all answers

Get 1 free homework help answer.
Already have an account? Log in
discord banner image
Join us on Discord
Chemistry Study Group
Join now

Related textbook solutions

Related questions

Weekly leaderboard

Start filling in the gaps now
Log in